*To*: TIMOTHY KREMANN <twksoa262 at verizon.net>*Subject*: Re: [isabelle] Isar Proof*From*: Tobias Nipkow <nipkow at in.tum.de>*Date*: Wed, 18 Jun 2008 10:03:13 +0200*Cc*: isabelle-users at cl.cam.ac.uk*In-reply-to*: <219881.17858.qm@web84005.mail.mud.yahoo.com>*References*: <219881.17858.qm@web84005.mail.mud.yahoo.com>*User-agent*: Thunderbird 1.5.0.7 (X11/20060909)

apply (metis)

Tobias TIMOTHY KREMANN wrote:

lemma"[| ALL x . (P (x::'a) => ~ Q x) /\(P x => ~ R x) /\ (Q x => ~ R x); EX x . P x; EX x . Q x; EX x . R x|] ==> EX x y z. (~((x::'a) = y) /\ ~( x = z) /\ ~( y = z))" apply(elim ex_forward) apply(auto) doneCan someone suggest an Isar equivalent for the above proof? Thanks, Tim

**References**:**[isabelle] Isar Proof***From:*TIMOTHY KREMANN

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