Re: [isabelle] Infinitely recursive lambda expression or not?
You could try Isabelle/HOLCF, but I’m not sure how well documented and supported it is.
On 27 Dec 2013, at 17:47, Yannick Duchêne (Hibou57) <yannick_duchene at yahoo.fr> wrote:
> Le Fri, 27 Dec 2013 18:33:49 +0100, Lawrence Paulson <lp15 at cam.ac.uk> a écrit:
>> From a computational point of view, "f a = (a ∨ f a)” must be regarded as undefined, because the recursion is not well-founded. There are logics where you could then prove that f(True)=True and f(False)=undefined.
>> Larry Paulson
> Interesting. Just out of curiosity and learn more (really not to use it), what are the names of these logics?
> “Syntactic sugar causes cancer of the semi-colons.” 
> “Structured Programming supports the law of the excluded muddle.” 
> : Epigrams on Programming — Alan J. — P. Yale University
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